python实现带界面的井字棋小游戏
目录
- 1、首先安装tkinter
- 2、初始化窗口
- 3、定义按钮
- 4、检查获胜的条件
今天我们用python+tkinter
安装带界面的井字棋,效果如图所示。
Tkinter
是 Python
的标准 GUI 库。Python
使用 Tkinter 可以快速的创建 GUI 应用程序。由于 Tkinter
是内置到 python 的安装包中、只要安装好 Python 之后就能 import Tkinter
库、而且 IDLE 也是用 Tkinter
编写而成、对于简单的图形界面 Tkinter
还是能应付自如。
pip install tkinter
1、首先安装tkinter
root= Tk() root.title('井字棋') digits = [1,2,3,4,5,6,7,8,9] mark = '' “ count = 0 panels = ["panel"]*10
2、初始化窗口
Label(root,text="player1 : X",font="times 15").grid(row=0,column=1) Label(root,text="player2 : O",font="times 15").grid(row=0,column=2) button1=Button(root,width=15,font=('Times 16 bold'),height=7,command=lambda:checker(1)) button1.grid(row=1,column=1) button2=Button(root,width=15,height=7,font=('Times 16 bold'),command=lambda:checker(2)) button2.grid(row=1,column=2) button3=Button(root,width=15,height=7,font=('Times 16 bold'),command=lambda: checker(3)) button3.grid(row=1,column=3) button4=Button(root,width=15,height=7,font=('Times 16 bold'),command=lambda: checker(4)) button4.grid(row=2,column=1) button5=Button(root,width=15,height=7,font=('Times 16 bold'),command=lambda: checker(5)) button5.grid(row=2,column=2) button6=Button(root,width=15,height=7,font=('Times 16 bold'),command=lambda: checker(6)) button6.grid(row=2,column=3) button7=Button(root,width=15,height=7,font=('Times 16 bold'),command=lambda: checker(7)) button7.grid(row=3,column=1) button8=Button(root,width=15,height=7,font=('Times 16 bold'),command=lambda: checker(8)) button8.grid(row=3,column=2) button9=Button(root,width=15,height=7,font=('Times 16 bold'),command=lambda: checker(9)) button9.grid(row=3,column=3) root.mainloop()
3、定义按钮
很明显上面的井字棋就是9个按钮。这里定义9个按钮。
def win(panels,sign): return ((panels[1] == panels[2] == panels [3] == sign) or (panels[1] == panels[4] == panels [7] == sign) or (panels[1] == panels[5] == panels [9] == sign) or (panels[2] == panels[5] == panels [8] == sign) or (panels[3] == panels[6] == panels [9] == sign) or (panels[3] == panels[5] == panels [7] == sign) or (panels[4] == panels[5] == panels [6] == sign) or (panels[7] == panels[8] == panels [9] == sign))
4、检查获胜的条件
检查获胜的条件,上面其中一种情况都是获胜的。
def checker(digit): global count, mark, digits if digit==1 and digit in digits: digits.remove(digit) if count%2==0: mark ='X' panels[digit]=mark elif count%2!=0: mark = 'O' panels[digit]=mar button1.config(text = mark) count = count+1 sign = mark if(win(panels,sign) and sign=='X'): msg.showinfo("Result","Player1 wins") root.destroy() elif(win(panels,sign) and sign=='O'): msg.showinfo("Result","Player2 wins") root.destroy()
最后这里是点击下棋,然后用win
函数判断是否结束比赛赢得棋局。
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