Python实现随机生成迷宫并自动寻路
目录
- Python深搜版:
- Python 广搜版
- lua版:
Python深搜版:
核心在于带随机的深搜(见代码第23到27行,其实也可以用22行代替这几行代码,你可以试着把第24行的数字4改大或者改小,即调整随机程度)
import os import random from queue import Queue import numpy import colorama from colorama import Fore, Back, Style import sys from bmpEditor import bmp colorama.init() # numpy.random.seed(1) _xy = [0,2,0,-2,0] size = 31 sys.setrecursionlimit(100000000) road = set() def dfs(curr_pos): road.add(curr_pos) # for i in numpy.random.permutation(4): p = [0,1,2,3] for i in range(4): l = random.randint(0,3) r = random.randint(0,3) p[l], p[r] = p[r], p[l] for i in p: next_pos = (curr_pos[0] + _xy[i], curr_pos[1] + _xy[i+1]) if (0<=next_pos[0]<size and 0<=next_pos[1]<size and next_pos not in road ): road.add(((curr_pos[0] + next_pos[0])/2, (curr_pos[1] + next_pos[1])/2)) dfs(next_pos) dfs((0,0)) q = Queue() q.put((0,0)) ans_road = set() def dfs_getans(curr_pos): # print(curr_pos) ans_road.add(curr_pos) if (size-1, size-1) in ans_road: return for i in range(4): next_pos = (curr_pos[0] + _xy[i]//2, curr_pos[1] + _xy[i+1]//2) if (0<=next_pos[0]<size and 0<=next_pos[1]<size and next_pos in road and next_pos not in ans_road and (size-1, size-1) not in ans_road): dfs_getans(next_pos) if (size-1, size-1) not in ans_road: ans_road.remove(curr_pos) dfs_getans((0,0)) for i in range(size): for j in range(size): print((Back.WHITE + ' ') if (i,j) in road else (Back.BLACK + ' '), end=' ') print() wall_width = 2 cell_size = 6 image = bmp((size+3)*cell_size-wall_width, (size+3)*cell_size-wall_width, 0x000000) for i in range(size+3): for j in range(size+3): if (i-1, j-1) in road: image.paint_rect(i*cell_size, j*cell_size, cell_size*2-wall_width, cell_size*2-wall_width, 0xffffff) file_name = "%dmaze.bmp"%size image.save_image(file_name) os.system(file_name) for p in ans_road: # image.paint_rect(p[0]+1, p[1]+1) image.paint_rect(( p[0]+1)*cell_size + (cell_size - wall_width)//2, (p[1]+1)*cell_size + (cell_size - wall_width)//2, cell_size, cell_size, 0xff0000 ) file_name = "%dans.bmp"%size image.save_image(file_name) os.system(file_name)
效果
3131:
8181:
坐标系有翻转,控制台中的左上角对应图片中的左下角
其中bmpEditor不是官方库,代码地址(文件名为bmpEditor.py,和这以上代码放同一个路径下即可)
Python 广搜版
在队列的基础上把队列中的元素顺序打乱(第24行)
import os import random from queue import Queue import numpy import colorama from colorama import Fore, Back, Style import sys import random from bmpEditor import bmp colorama.init() numpy.random.seed(1) _xy = [0,2,0,-2,0] size = 59 sys.setrecursionlimit(size*size//4+size) q = [] q.append((0,0)) road = set() road.add((0,0)) while len(q) != 0: random.shuffle(q) curr_pos = q.pop() # print(curr_pos) for i in range(4): next_pos = (curr_pos[0] + _xy[i], curr_pos[1] + _xy[i+1]) if ( 0<=next_pos[0]<size and 0<=next_pos[1]<size and next_pos not in road ): road.add( ((curr_pos[0] + next_pos[0])//2, (curr_pos[1] + next_pos[1])//2) ) q.append(next_pos) road.add(next_pos) ans_road = set() def dfs_getans(curr_pos): ans_road.add(curr_pos) if (size-1, size-1) in ans_road: return for i in range(4): next_pos = (curr_pos[0] + _xy[i]//2, curr_pos[1] + _xy[i+1]//2) if ( 0<=next_pos[0]<size and 0<=next_pos[1]<size and next_pos in road and next_pos not in ans_road and (size-1, size-1) not in ans_road): dfs_getans(next_pos) if (size-1, size-1) not in ans_road: ans_road.remove(curr_pos) dfs_getans((0,0)) print(len(ans_road)) for i in range(0, size): for j in range(0, size): print((Back.WHITE + ' ') if (i,j) in road else (Back.BLACK + ' '), end=' ') print() wall_width = 1 cell_size = 5 image = bmp((size+3)*cell_size-wall_width, (size+3)*cell_size-wall_width, 0x000000) for i in range(size+3): for j in range(size+3): if (i-1, j-1) in road: image.paint_rect(i*cell_size, j*cell_size, cell_size*2-wall_width, cell_size*2-wall_width, 0xffffff) file_name = "%dmaze.bmp"%size image.save_image(file_name) os.system(file_name) for p in ans_road: # image.paint_rect(p[0]+1, p[1]+1) image.paint_rect(( p[0]+1)*cell_size + (cell_size - wall_width)//2, (p[1]+1)*cell_size + (cell_size - wall_width)//2, cell_size, cell_size, 0xff0000 ) file_name = "%dans.bmp"%size image.save_image(file_name) os.system(file_name)
效果:
相比深度优先的,这种迷宫会更加“直”一些
lua版:
大体上是深搜,加了一定的随机性使得搜索过程中有一定概率暂时放弃当前路径。见表stop_points,(第7行、第74行及其后面的repeat循环)
local _xy = {0,2,0,-2,0} local size = 41 local base = size+1 local road = {} stop_points = {} function dfs(curr_x, curr_y) road[curr_x*base+curr_y] = true if math.random(1,10) <= 3 then stop_points[curr_x*base+curr_y] = true return end -- os.execute("cls") -- print_map() local permutation = {1,2,3,4} for i=1, 4 do local l = math.random(1,4) local r = math.random(1,4) permutation[l], permutation[r] = permutation[r], permutation[l] end for i=1, 4 do local next_x = curr_x+_xy[permutation[i]] local next_y = curr_y+_xy[permutation[i]+1] if next_x>=1 and next_x<=size and next_y>=1 and next_y<=size and road[next_x*base+next_y] == nil then local mid_x = math.floor((curr_x+next_x)/2) local mid_y = math.floor((curr_y+next_y)/2) road[mid_x*base+mid_y] = true dfs(next_x, next_y) end end end local ans_geted = false local parent = {} function get_ans(curr_x, curr_y) -- print(curr_x, curr_y) for i=1, 4 do next_x = (curr_x + math.floor(_xy[i])/2 ) next_y = (curr_y + math.floor(_xy[i+1])/2 ) -- print(next_x, next_y) if next_x >= 1 and next_x <= size and next_y >= 1 and next_y <= size and road[next_x*base+next_y] and parent[next_x*base+next_y]==nil then parent[next_x*base+next_y] = curr_x*base+curr_y get_ans(next_x, next_y) end end end local ans_road = {} function print_map() for i=0, size+1 do local line = "" for j=0, size+1 do if ans_road [i*base+j] then line = line..".." elseif road[i*base+j]==true then line = line.." " else line = line.."HH" end end print(line) end end stop_points[1*base+1] = true -- create maze repeat local has_point = false for v,_ in pairs(stop_points) do has_point = true stop_points[v] = nil dfs(math.floor(v/base), v%base) break end -- print(has_point) until not has_point get_ans(1,1) parent[1*base+1] = nil print("") -- for k,v in pairs(parent) do -- print(string.format("[%d,%d]->[%d,%d]", math.floor(k/base), k%base, math.floor(v/base), v%base)) -- end print("") local x = size local y = size repeat -- print(x,y) ans_road[x*base+y] = true local v = parent[x*base+y] x = math.floor(v/base) y = v%base until --[[(x==1 and y== 1)]] not parent[x*base+y] ans_road[1*base+1] = true print_map()
效果:
4141:
8989
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